B.OD.
i. mu dot z = mu
ii. sigma overline z = sqrt((p(1 - p))/n)
iii. mu dot p = np
iv. sigma overline z = sqrt((p(1 - p))/n)
Which answer shows
i. The mean of the distribution of
ii. The standard deviation of the distribution of
iii. The mean of the distribution of p
iv. The standard deviation of the distribution of pA
i. mu hat p = np
ii. sigma overline x = sqrt(np(1 - p))
iii mu overline p = sqrt(np(1 - p))
IV. sigma hat p = sqrt((p(1 - p))/n)
1. mu overline x = mu
i.
sigma overline x = sigma/(sqrt(n))
i mu hat p =p
iv. sigma overline p = sqrt((p(1 - p))/n)
B.A
i. mu hat p = np
ii. sigma overline x = sqrt(np(1 - p))
iii mu overline p = sqrt(np(1 - p))
IV. sigma hat p = sqrt((p(1 - p))/n)
1. mu overline x = mu
i.
sigma overline x = sigma/(sqrt(n))
i mu hat p =p
iv. sigma overline p = sqrt((p(1 - p))/n)
B.OD. mu dot z = mu
i mu dot z = np
- mu dot p = np sigma overline z = sqrt((p(1 - p))/n)
iv sqrt(np(1 - p))
sigma overline z = sqrt((p(1 - p))/n)
mu dot 3 =p sigma overline p = sigma/(sqrt(n))E. 1 mu hat z =p
sigma overline x = sigma/(sqrt(n))
mu dot p = overline x
IV sigma dot p = sqrt((p(1 - p))/n)
1 answer
1 answer