Which answer below correctly sets up the formula for finding the x-coordinate of the vertex of y=x2+6x+3

Question

?(1 point)
Responses

x=−62(1)
x is equal to the fraction with numerator negative 6 and denominator 2 times 1

x=32(1)
x is equal to the fraction with numerator 3 and denominator 2 times 1

x=−32(6)
x is equal to the fraction with numerator negative 3 and denominator 2 times 6

x=62(1)
x is equal to the fraction with numerator 6 and denominator 2 times 1

Answer 1

To find the x-coordinate of the vertex of a quadratic equation in the form \(y = ax^2 + bx + c\), you can use the formula:

\[ x = -\frac{b}{2a} \]

In your equation \(y = x^2 + 6x + 3\), we have \(a = 1\) and \(b = 6\). Plugging these values into the formula gives:

\[ x = -\frac{6}{2(1)} \]

This means the correct choice is:

x = -6 / (2 * 1)

which corresponds to:

x=−62(1)

So, the correct response is:

x=−62(1) x is equal to the fraction with numerator negative 6 and denominator 2 times 1.