Whew. long question.

Question

Barium carbonate is the source of barium compounds. It is produced in an aqueous precipitation reaction from barium sulfide and sodium carbonate. (Barium sulfide is a soluble compound obtained by heating the mineral barite, which is barium sulfate, with carbon.) What are the molecular equation and net ionic equation for the precipitation reaction? A solution containing 33.9 g of barium sulfide requires 21.2 g of sodium carbonate to react completely with it, and 15.6 of sodium sulfide is produced in addition to whatever barium carbonate is obtained. How many grams of barium sulfide are required to produce 10.0 tons of barium carbonate?

BaS(aq)+Na2CO3(aq)->BaCO3(s)+Na2S(aq)

Ba+2(aq)+CO3-2(aq)->BaCO3(s)

7.78(with a line showing sig figs)41266 x 10^6 g BaS

Answer 1

I worked it and got 7.7876 x 10^6 which I would round to 7.79*10^6. I checked the conversions with an on-line calculator and it converted to 7.7875 x 10^6. I used 169.393 for the molar mass of BaS, 197.33 for the molar mass of BaCO3, 2000 lbs in a ton and 453.59 g in a pound.