Whenever w is an integer greater than 1, log(w) w^2 / w^6 =?

Question

F. -4
G. -3
H. -1 / 3
J. 1 / 3
K. 3

Answer 1

looking at the choices of answer I must conclude that you meant:

log_w (w^2/w^6)
= log_w w^2 - log_w (w^6)
= 2 log_ww/(6log_ww)
= 2/6
= 1/3

Answer 2

wouldn't the power be -4? 2 - 6

Answer 3

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