I don't know what polygons you drew, but consider this: no matter what path you took, if at any point you are turned to the left of where you started, you must have turned through 90 degrees (plus some integer number of full turns); if at any point you are turned backward compared to where you started, you must have turned through 180 degrees (plus some number of full turns).
And finally, if you are facing the direction you started in, you must have turned through zero degrees (plus some integer number of full turns).
When you walk around a polygon, at each vertex you need to turn either right (clockwise) or left (counterclockwise). A turn to the left is measured by a positive number of degrees and a turn to the right by a negative number of degrees. Find the sum of the measures of the turn angles of the polygons you drew. Assume you start at a vertex facing in the direction of a side, walk around the polygon, and end up at the same vertex facing in the same direction as when you started
2 answers
I think the purpose of your experiment was to show that for any polygon, the sum of the exterior angles will always be 360º
(the simplest example would be to totally walk around a normal city block. You will have made 4 90º turns.)
(the simplest example would be to totally walk around a normal city block. You will have made 4 90º turns.)
2 answers