When you drop a 0.38 kg apple, Earth exerts

Question

a force on it that accelerates it at 9.8 m/s^2
toward the earth’s surface. According to Newton’s third law, the apple must exert an equal
but opposite force on Earth.If the mass of the earth 5.98 × 1024 kg, what
is the magnitude of the earth’s acceleration
toward the apple?

Answer in units of m/s2
Don't understand. Please help

Answer 1

the Earth and the apple attract each other with equal force

because the mass of the Earth is about 25 orders of magnitude greater
... the Earth's acceleration toward the apple is comparably less

a = f / m = (.38 * 9.8) / 5.98E24