when you count by one from many intergers, you are counting consecutive integer. Using variable, the consecutive intergers are n, n+ 1 and n + 2. The sum of the the consecutive integers is 48. What are the integers?

Answer 1

Let's assume that the first integer is represented by the variable 'n'.

According to the given information, the consecutive integers are n, n+1, and n+2.

To find the sum of the consecutive integers, we can add them together:
n + (n+1) + (n+2) = 48

Simplifying the equation by combining like terms:
3n + 3 = 48

Subtracting 3 from both sides of the equation:
3n = 45

Dividing both sides of the equation by 3:
n = 15

So the first integer is 15.

The second integer is n+1 = 15+1 = 16.

The third integer is n+2 = 15+2 = 17.

Therefore, the three consecutive integers that have a sum of 48 are 15, 16, and 17.