value=3x^2-2y^2 - 2x^2+3y
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3^2-2*5^2+3(5)
when x=3 and y=5 how much does the value of 3x to the seond power minus 2y to the second power exceed the value of 2x to the second power minus 3y
2 answers
Given
f(x,y) = ((3x)²-(2y)²) - ((2x)²-3y)
Find f(3,5).
f(3,5)
=((3*3)²-(2*5)²)-((2*3)²-3*5)
=(9²-10²)-(6²-15)
=(81-100)-(36-15)
=-19-21
=-40
Please check if the interpretation of the question is correct.
f(x,y) = ((3x)²-(2y)²) - ((2x)²-3y)
Find f(3,5).
f(3,5)
=((3*3)²-(2*5)²)-((2*3)²-3*5)
=(9²-10²)-(6²-15)
=(81-100)-(36-15)
=-19-21
=-40
Please check if the interpretation of the question is correct.
1 answer