When using the Heisenberg uncertainty principle, and you are seeking to find delta x, and are given both the velocity and delta v, does the velocity even matter? The equation only states that h/ (4 times pi times mass times delta v) = delta x.

Answer 1

you have the formula correct. in acatuality, delta V is greater with greater velocity (measurements are precise to only so many digits)

Answer 2

So for example, if there was an electron mass of 6.24 times 10^-20 kg, moving at a velocity of 4.5 times 10^8 m/s, and we were given delta v as .01 times 10^8 m/s, the equation would be

h/ (4 times pi times (6.24 times 10^-20) times (.01 times 10^8))

or do we plug in 4.5 times 10^8?

Answer 3

No. v doesn't matter.