When using an elimination strategy to solve the system 3a^2=17-5t and
7a+24=3a^2-2t, the variable that can be eliminated is
A. a
B. a^2
C. t
D. an elimination strategy cannot be used with this system
2 answers
omg i waited for a good 2 minutes before I realized hahaha
reformatting the equations, you have
3a^2 + 5t = 17
3a^2-7a-2t = 24
eliminating t, you have
6a^2 + 10t = 34
15a^2-35a-10t = 120
21a^2 - 35a - 154 = 0
3a^2 - 5a - 22 = 0
solve as usual for a, then find t
3a^2 + 5t = 17
3a^2-7a-2t = 24
eliminating t, you have
6a^2 + 10t = 34
15a^2-35a-10t = 120
21a^2 - 35a - 154 = 0
3a^2 - 5a - 22 = 0
solve as usual for a, then find t
2 answers