When trying to solve the quadratic equation x2+4x−5=7

, George provided his work in the table.

What did he do wrong?

(1 point)

1 answer

To determine what George might have done wrong when solving the quadratic equation \( x^2 + 4x - 5 = 7 \), we first need to simplify the equation correctly.

  1. Starting with the equation:
    \( x^2 + 4x - 5 = 7 \)

  2. Rearranging the equation:
    Subtract 7 from both sides to set the equation to zero:
    \( x^2 + 4x - 5 - 7 = 0 \)
    This simplifies to:
    \( x^2 + 4x - 12 = 0 \)

So the correct equation to solve is \( x^2 + 4x - 12 = 0 \).

If George provided a table, it is possible that he either solved the equation incorrectly due to an error in rearranging or did not correctly find the roots of the simplified equation.

Without seeing the actual work in the table, we can generally conclude that the mistake likely occurred in either the initial steps of moving the constant term (7) to the left side, or perhaps in computing the roots of the resulting quadratic equation \( x^2 + 4x - 12 = 0 \).

If you have specific entries in George's table, please provide them for a more precise identification of the error.