current price ---- x
increased price ---- x+5
200/x - 200/(x+5) = 2
Solve for x, reject the negative answer.
I suggest you multiply each term by x(x+5) to get the quadratic
when the price of an item was increased by sh.5, i bought 2 items fewer with sh 200. what is the current price of the item?
10 answers
Let the original price of the item be x
New price of the item be x+5
Then:
200/x -200/x+5 =2
200(x+5) -200x =2x(x+5)
200x + 1000 -200x =2x^2 +10x
2x^2 +10x-1000 =0
x^2 +5x -500=0
Product= -500
Sum =5
(25,-20)
x^2 +25x -20x -500 =0
x(x +25) -20(x+25) =0
x-20 =0
x=20
Or
X+25 =0
x= -25
Since the price cannot be a negative we take the positive value therefore the final answer is 20
New price of the item be x+5
Then:
200/x -200/x+5 =2
200(x+5) -200x =2x(x+5)
200x + 1000 -200x =2x^2 +10x
2x^2 +10x-1000 =0
x^2 +5x -500=0
Product= -500
Sum =5
(25,-20)
x^2 +25x -20x -500 =0
x(x +25) -20(x+25) =0
x-20 =0
x=20
Or
X+25 =0
x= -25
Since the price cannot be a negative we take the positive value therefore the final answer is 20
Very wrong please make a video
I dont really understand
Very nice
Very nice
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i underatood✌
the final answer is 25
current price is (x+5)=(20+5)
current price is (x+5)=(20+5)
Let the original price of an item be
x
Let the number of items be y
(x+5)(y-2)=200...(i)
xy=200..(ii)
y=200/x..(iii)
From (i)
xy-2x+5y-10=200..(iv)
Substitute (iii) in (iv)
x(200/x)-2x+1000/x-210=0
200-210-2x+1000/x=0
-10-2x+1000/x=0
-10x-2x²+1000=0
x²+5x-500=0
x²+25x-20x-500=0
x(x+25)-20(x+25)=0
(x-20)(x+25)=0
But x≠-25 since x>0
Therefore
x=sh 20
y=200/20=10 items
x
Let the number of items be y
(x+5)(y-2)=200...(i)
xy=200..(ii)
y=200/x..(iii)
From (i)
xy-2x+5y-10=200..(iv)
Substitute (iii) in (iv)
x(200/x)-2x+1000/x-210=0
200-210-2x+1000/x=0
-10-2x+1000/x=0
-10x-2x²+1000=0
x²+5x-500=0
x²+25x-20x-500=0
x(x+25)-20(x+25)=0
(x-20)(x+25)=0
But x≠-25 since x>0
Therefore
x=sh 20
y=200/20=10 items