pH = pKa + log (base)/(acid)
So if pH = pKa then log (base)/(acid) must = 0 and (base/(acid) = 1 so (base) = (acid) so is that 50%?
When the pH of a buffer is equal to its pKa, what is the amount of dissociation that has occurred?
1 %
25 %
50 %
100 %
2 answers
50%