When the following reaction reaches equilibrium, the concentrations are 2.26 M A, 0.50 M B, and 2.00 M C. Calculate the equilibrium constant.
A+2B<=====>3C
2 answers
Kc=0.884 with no unit
A+2B<=====>3c
Kc=[c]3/[A][b]2
Kc=[2.00]3 /[2.26][0.5]2
Kc=8.365/[2.26][0.25]
Kc=8.365/0.565
Kc=14.8
Kc=[c]3/[A][b]2
Kc=[2.00]3 /[2.26][0.5]2
Kc=8.365/[2.26][0.25]
Kc=8.365/0.565
Kc=14.8