Here are the half equations.
MnO2 + 4 OH^- ==> MnO4^- + 3e + 2H2O
H2O + 2e + HO2^- ==> 3 OH^-
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Multiply equation 1 by 2 and equation 2 by 3 and add them to obtain the final balanced ionic equation in basic solution. After you have done this don't forget to look for common ions on each side of the equation; probably you will find some that appear on both sides. You can cancel ions that appear on both side (of course you can cancel only enough on each side to keep things equal). For example, I can tell that you will have H2O on both sides and you will have OH^- on both sides. Of course the electrons will cancel.
When the equation for the following reaction in basic solution is balance, what is the sum of the coefficients?
MnO2 + HO2^1-.....>MnO4^1-
A=11
B=31
C=14
D=9
3 answers
D)9
D)9