When the dried-up seed pod of a scotch broom plant bursts open, it shoots out a seed with an initial velocity of 2.64 m/s at an angle of 30.0˚ below the horizontal. The seed pod is 0.465 m above the ground.

Question

How long does it take for the seed to land?
What horizontal distance does it cover during its flight?

Answer 1

For the time, solve the equation

y = 0.465 + 2.64 sin30 -(g/2) t^2 = 0
= 0.465 + 1.32 -4.9 t^2
There will be two solutions. Take the positive one.

For the horizonal distance traveled, that would be

X = 2.64 cos30*t = 2.29 t
Use the t from the first part.

Answer 2

shouldn't 2.64 (sin30) by multiplied by time?

y = 0.465 + 2.64 (sin30)t -(g/2) t^2 = 0

Answer 3

Yes, thanks for catching that. :-)

0 = 0.465 + 1.32 t -4.9 t^2
also needed a "t" in it.

Answer 4

Where did you get -4.6 from?

Answer 5

I mean -4.9