When the break are applied to a moving car travelling at 60km/hr at decelerate at a uniform rate of 5m/s^2. .calculate the time taken to reach a velocity of 36km/hr

Answer 1

a = -5 m/s^2
60 km/h = 60000/3600 m/s = 50/3 m/s
36 km/h = 10 m/s

v = at + c
v = -5t + c
at start of event, t = 0, v = 50/3
50/3 = 0+c
so v = -5t + 50/3

solve for t when v = 10 m/s
10 = -5t + 50/3
t = 4/3 seconds

Answer 2

when the breaks are applied to a moving car travelling at 60km/hr at decelerate at a uniform rate of 5m/s^2.calculate the time taken to a reach a velocity of 36km/hr.

Answer 3

4/3

Answer 4

-1.34