S (s) + O2 (g) --> SO2(g)
2SO2 (g) + O2 (g) <--> 2 SO3 (g)
now using appropriate mol ratios you can solve...
3.4 x 10^24 S atoms (1 mol S/avagadros #)(2 mol SO3/1 mol S)
then you can use the mols of SO3 to solve for g (using molecular mass) and then litres...
when sulfur is burned in the presence of oxygen, sulfur trioxide is produced. if 3.4 x 10^24 atoms of sulfur react, how many liters of sulfur trioxide are produced?
1 answer