I don't agree with the equation because you can't isolate CaO. It immediately reacts with H2O to form CaOH)2 as I've indicated in the equation below. However, none of that changes the stoichiometry of the equation and 1 mol Ca still produces 1 mol H2 gas.
Ca + 2H2O --> Ca(OH)2 + H2
mols Ca = grams Ca/atomic mass Ca = ?
1 mol Ca produces 1 mol H2 gas.
That 1 mol H2 gas will be dry H2 gas. Use PV = nRT and solve for V in liters at the conditions listed.
When solid calcium is placed in water, it undergoes a vigorous reaction that produces solid calcium oxide, CaO(s) and hydrogen gas. determine the volume of dry hydrogen gas that is produced when 5.00 g of calcium reacts and the gas is collected at 42 degrees celsius and 770 mmHg.
Ca (s) + H2O (l) = CaO (s) + H2 (g)
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