55 = 60/11 √d
10.08 = √d
101.67 = d
When sky divers initially fall from an airplane their velocity v in miles per hour after free falling d feet can be approximated by v=60/11√d. (Because of air resistance, they will eventually reach terminal velocity.) How far do sky divers need to fall to attain a velocity of 55 miles per hour? (This value for d represents the minimum distance.)
A sky diver needs to fall about ? feet to attain a velocity of 55mph.
2 answers
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