Ask a New Question

when sin theta+cos theta=square root of 2,find the solution of sin^3 theta+cos^3 theta

1 answer

sum of two cubes..

a^3+b^3= (a+b)(a^2-ab+b^2)

= (sinT+cosT)(Sin^2T+cos^2T-sinTcosT)
= sqrt2 (1-sinTcosT)

Ask a New Question or answer this question.

Similar Questions

What is a simplified form of the expression (sec^3 theta) - (sec theta/cot^2 theta)?a. 0 b. sec theta-tan theta c. cos theta d.
1. 6 answers
Which of the following are trigonometric identities? Select all that apply (there are 3 answers).A cos^2(theta)=sin^2(theta)-1 B
1. 5 answers
1. sin^2 theta+cos theta=2 (Hint: Use the Pythagorean identity sin^2 theta+cos theta=1 to replace sin^2 theta in the given
1. 1 answer
Which trigonometric functions are equivalent to tan(theta)? Select all that apply. (2 answers)a. -tan(-theta)**** b. -tan(theta)
1. 2 answers

more similar questions