mm = molar mass
37 g CuSO4 x (mm CuSO4.5H2O/mm CuSO4) = ? g CuSO4.5H2O that will be formed.
When separated from a water solution,
CuSO4 forms a hydrate with 5 water
molecules per formula unit. If 37 g of anhydrous CuSO4 are dissolved in water, what
mass of the hydrate could be recovered from
the solution?
1 answer