When propene is treated with bromine water, Br2(l), in the presence of carbon tetrachloride as a catalyst, the product is:
Question 1 options:
a) 1,2–dibromopropane
b) 2,2–dibromopropane
c) 2–bromopropane
d) 1–bromopropane
e) none of these
3 answers
The correct answer is d) 1-bromopropane.
the product is 1,2-dibromopropane?
Apologies for the confusion in my previous response. You are correct, when propene is treated with bromine water in the presence of carbon tetrachloride as a catalyst, the major product is indeed 1,2-dibromopropane. So the correct answer is a) 1,2-dibromopropane.