Asked by Ari
When potential difference across the terminals of a battery is measured using an analogue voltmeter of resistance 95 ohms, the reading on the voltmeter is 5.70 V. When it is measured using a very high resistance digital meter the reading is 6.00 V. What is the internal resistance of the battery?
Answers
Answered by
henry2,
I = V/Rm = 5.70/95 = 0.06A.
r = V/I = (6-5.7)/0.06 = 0.30/0.06 = 5. Ohms.
r = V/I = (6-5.7)/0.06 = 0.30/0.06 = 5. Ohms.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.