To solve this problem, we need to determine the equations of lines that are parallel and perpendicular to the given equation of the sidewalk, which is \(2x - y = 7\).
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Finding the slope of the original line: We can rewrite the equation in slope-intercept form \(y = mx + b\): \[ y = 2x - 7 \] From this, we can see that the slope (\(m\)) of the original line is \(2\).
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Finding the equations of lines parallel to the original line: Parallel lines have the same slope. Therefore, any line parallel to \(2x - y = 7\) will also have a slope of \(2\). These lines can be represented in the form: \[ y = 2x + b \] where \(b\) can be any real number.
Some possible parallel line equations could be:
- \(y = 2x + 1\)
- \(y = 2x - 3\)
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Finding the equation of a line perpendicular to the original line: Perpendicular lines have slopes that are negative reciprocals of each other. The slope of the original line is \(2\), so the slope of a perpendicular line would be \(-\frac{1}{2}\). The equation of a perpendicular line can be represented in the form: \[ y = -\frac{1}{2}x + b \] where \(b\) can again be any real number.
A possible perpendicular line equation could be:
- \(y = -\frac{1}{2}x + 3\)
Answers:
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The equations of the two walkways parallel to the first walkway COULD be:
- \(y = 2x + 1\)
- \(y = 2x - 3\)
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The equation of the walkway perpendicular to the first walkway COULD be:
- \(y = -\frac{1}{2}x + 3\)
You can replace the above equations with any other equations meeting the criteria mentioned.