.002301 moles because .0195 L x .118
.002301/.017 =molarity(concentration)
Answer 0.135mol/L concentration
When one student did this experiment, he started with 19.5 mL of 0.118 M monoprotic acid. The endpoint was reached when 17 mL of base was added. What was the concentration of the base?
2 answers
alison is assuming also a monoprotic base.