M1*d1 = M2*d2.
M1*1.2 = M2*1.5, M1 = 1.25M2.
(M1+14)*1.8 = M2*3.
(1.25M2+14)1.8 = 3M2,
2.25M2 + 25.2 = 3M2, M2 = 33.6 kg, F2 = M2*g = 33.6*9.8 = 329.3 N. = Wt. of the girl.
M1 = 1.25M2 = 1.25*33.6 = 42 kg,
F1 = 42*9.8 = 411.6 N. = Wt. of the boy.
when one boy is sitting 1.20 meter from the center of he seesaw the girl must sit on the other side 1.50 meter from the center to maintain an even balance . however the boy carries an additional mass pf 14 kg and sit 1.80 meter from the center the girl must move to 3 meter from the center to balance . neglecting the weight of the seesaw find the weight of the boy and the girl?
please help me this is badly needed. i need to pass this tomorrow. im hoping for your response.
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