To calculate how much money will be in the savings account after 18 years, we can use the formula for compound interest, which is:
\[ A = P(1 + r)^t \]
Where:
- \( A \) is the amount of money accumulated after \( t \) years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (decimal).
- \( t \) is the number of years the money is invested or borrowed.
In this case:
- \( P = 1000 \) (the initial amount)
- \( r = 0.08 \) (8% interest rate)
- \( t = 18 \) (the number of years)
Now, substituting the values into the formula:
\[ A = 1000(1 + 0.08)^{18} \]
Calculating inside the parentheses:
\[ A = 1000(1.08)^{18} \]
Now calculating \( (1.08)^{18} \):
\[ (1.08)^{18} \approx 4.0357 \]
Now multiplying:
\[ A \approx 1000 \times 4.0357 \approx 4035.70 \]
Therefore, after 18 years, Nico will have approximately $4035.70 in his savings account.