In the formation of NaCl (sodium chloride), the correct action that occurs between the reacting elements is:
Sodium donates an electron to chlorine.
Sodium (Na) has one electron in its outer shell and tends to lose that electron, becoming positively charged (Na⁺), while chlorine (Cl), which has seven electrons in its outer shell, tends to gain an electron to complete its octet, becoming negatively charged (Cl⁻). The attraction between these oppositely charged ions forms the ionic bond in NaCl.