When mapping ∆ D(-5,0)E(-3,0)F(-3,4) onto ∆ J(1,2)K(1,4)L(5,4) to prove they are congruent, which of the following identifies a pair of corresponding parts that are also congruent?

a. D ≅ L
b. F ≅ J
c. DE ≅ JK
d. DF ≅ KL

1 answer

To determine which pairs of parts are congruent when mapping triangle ∆ DEF onto triangle ∆ JKL, we should analyze the vertices and the sides of both triangles.

  1. Vertices of ∆ DEF:

    • D(-5, 0)
    • E(-3, 0)
    • F(-3, 4)
  2. Vertices of ∆ JKL:

    • J(1, 2)
    • K(1, 4)
    • L(5, 4)

Next, we can calculate the lengths of the sides in each triangle to compare corresponding parts.

Lengths of sides in ∆ DEF:

  • DE: The length between points D(-5,0) and E(-3,0) is calculated by: \[ DE = |-5 - (-3)| = | -5 + 3 | = 2 \]

  • EF: The length between points E(-3,0) and F(-3,4) is: \[ EF = |0 - 4| = 4 \]

  • DF: The length between points D(-5,0) and F(-3,4) is calculated using the distance formula: \[ DF = \sqrt{(-3 - (-5))^2 + (4 - 0)^2} = \sqrt{(2)^2 + (4)^2} = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5} \]

Lengths of sides in ∆ JKL:

  • JK: The length between points J(1,2) and K(1,4) is: \[ JK = |2 - 4| = 2 \]

  • KL: The length between points K(1,4) and L(5,4) is: \[ KL = |1 - 5| = 4 \]

  • JL: The length between points J(1,2) and L(5,4) is: \[ JL = \sqrt{(5 - 1)^2 + (4 - 2)^2} = \sqrt{(4)^2 + (2)^2} = \sqrt{16 + 4} = \sqrt{20} = 2\sqrt{5} \]

Corresponding Parts:

Now we can compare:

  • DE (2) corresponds to JK (2).
  • EF (4) corresponds to KL (4).
  • DF (2√5) corresponds to JL (2√5).

Now, let's analyze the options given: a. D ≅ L (not true, as they have different coordinates).
b. F ≅ J (not true, as they have different coordinates).
c. DE ≅ JK (this is true; both have length 2).
d. DF ≅ KL (not true, DF ≅ JL).

Conclusion:

The correct answer is: c. DE ≅ JK