When magnesium metal and an aqueous solution of hydrochloric acid combine, they produce an aqueous solution of magnesium chloride and hydrogen gas. Using the equation, Mg (s) + 2HCl (aq) Imported Asset MgCl2 (aq) + H2 (g), if 72.9 g of Mg and 146.0 g of HCl are allowed to react, identify the limiting reagent.
Mg
HCl
MgCl2
H2
QUESTION 8
When magnesium metal and an aqueous solution of hydrochloric acid combine, they produce an aqueous solution of magnesium chloride and hydrogen gas. Using the equation, Mg (s) + 2HCl (aq) Imported Asset MgCl2 (aq) + H2 (g), if 48.6 g of Mg and 150.0 g of HCl are allowed to react, identify the limiting reagent.
Mg
HCl
MgCl2
H2
QUESTION 9
The number of moles of the reagent in excess can be used to calculate the moles of the products of the reaction.
TRUE
FALSE
QUESTION 10
Ammonia gas is formed from nitrogen gas and hydrogen gas according to the following equation: N2 (g) + 3H2 (g) Imported Asset 2NH3 (g). If 112 grams of nitrogen gas is allowed to react with an excess of hydrogen gas to produce 120 grams of ammonia, what is the percent yield of this reaction?
44.1%
66.2%
88.3%
96.4%
QUESTION 11
Ammonia gas is formed from nitrogen gas and hydrogen gas, according to the following equation: N2 (g) + 3H2 (g) Imported Asset 2NH3 (g). If 84.0 g of nitrogen gas is allowed to react with an excess of hydrogen gas to produce 85.0 g of ammonia, what is the percent yield of this reaction?
42.2%
65.0%
70.3%
83.3%
QUESTION 12
Ammonia gas is formed from nitrogen gas and hydrogen gas, according to the following equation, N2 (g) + 3H2 (g) Imported Asset 2NH3 (g). If 140 grams of nitrogen gas is allowed to react with an excess of hydrogen gas to produce 155 grams of ammonia, what is the percent yield of this reaction?
45.5%
67.0%
82.4%
91.2%
3 points Save Answer
QUESTION 13
The actual yield is usually less than the predicted (theoretical) yield.
TRUE
FALSE
2 points Save Answer
QUESTION 14
The theoretical yield for a chemical reaction can not be calculated until the reaction is completed.
TRUE
FALSE
4 answers
Mg
HCl
MgCl2
H2
I assume imported asset means arrow. You can write an arrow a little easier like this. --> or ==> or >>>.
Mg + 2HCl ==> MgCl2 + H2
mols Mg = grams/atomic mass = 72.9/24.3 = 3
mols HCl = 146/35.5 = 4.12
If Mg is the limiting reagent (LR) all of it will be used. How much HCl is needed? That will be
mols HCl needed = 3 mol Mg x (2 mols HCl/1 mol Mg) = 6 mols HCl. You don't have that much HCl; therefore, Mg can't be the LR which means HCl must be the LR. I always like to check that to see that I didn't make an error. So now we ask ourselves if HCl is the LR, all of it will be used. How much Mg is needed? That's
4.12 mols HCl x (1 mol Mg/2 mols HCl) = 4.12 x 1/2 = 2.06 mols Mg needed. Do you have that much Mg. Yes, so HCl is the LR, all of it will be used, and some of the Mg will be used but some will be left unreacted. Mg is the reagent in excess.
For the others, posting multiple questions with one posts USUALLY results in nothing being answered because it takes too much time for a single post. You might consider posting these as single posts; however, I SUGGEST YOU SHOW HOW YOU THINK EACH SHOULD BE SOLVED OR TELL US EXACTLY WHAT YOU DON'T UNDERSTAND.