if their ages now are Lee,Kevin,Kate = x,y,z,
a years ago, Kate was 27
b years ago, Lee was 38
x+y+z = 143
x-a = 27
z-a = 3(y-a)
x-b = 38
2(y-b) = z-b
Now just solve for x,y,z
It might be easier to eliminate a and b first, so you just have 3 equations to solve.
When Lee was thrice as old as Kevin, his sister Kate was twenty seven. When Kevin was half as old as Kate, then brother Lee was thirty eight. Their ages add to one forty three. How old are Kevin, Kate, and Lee?
2 answers
Answer:
Lee = 57
Kevin = 35
Kate = 51
Is this right?
Lee = 57
Kevin = 35
Kate = 51
Is this right?