I assume you meant
y^2 - 12y + k
Recall that (y+p)^2 = y^2 + 2py + p^2
So, you have 2py = -12y, so p = -6
Now what is p^2 = k?
When 'k' is added to the expression y² - 12, the expression becomes (y+p)². Find the values of 'p' and 'k'.
4 answers
Pls can you solve it into details
No
No understanding for the answer