The expression -8/(x+6)^2 is equal to zero when the numerator, -8, is equal to zero. However, since -8 cannot be divided by any number to give zero, there are no values of x for which the expression is equal to zero.
The expression is undefined when the denominator, (x+6)^2, is equal to zero. To find when this occurs, we set the denominator equal to zero and solve for x:
(x+6)^2 = 0
Taking the square root of both sides, we have:
x+6 = 0
x = -6
Therefore, the expression is undefined for x = -6.
When is -8/(x+6)^2 equal to zero or undefined
1 answer
1 answer