convert the photon wavelenght to energy, in ev.
subtract the 7.5eV, and you have it.
E=PlancksConstant*speedlight/lambda
h=4.15)×10−15 eV s
When irradiated with a radiation of wavelength 58.4 nm the electron of H atom was ejected
with kinetic energy 7.6 eV. Calculate the ionization energy.
1 answer