Let's first look at the original balanced equation:
\[ 2H_2 + 1O_2 \rightarrow 2H_2O \]
If you change \( 2H_2 \) to \( 3H_2 \), the new unbalanced equation would be:
\[ 3H_2 + O_2 \rightarrow ? \]
Now, to balance the equation, we need to determine how many water molecules (H2O) would be produced.
Starting with 3 molecules of hydrogen (H2):
- Each H2 molecule contains 2 hydrogen atoms, so \( 3H_2 \) provides \( 3 \times 2 = 6 \) hydrogen atoms.
- Each water molecule (H2O) requires 2 hydrogen atoms to form.
To find the number of water molecules produced:
- The number of water molecules that can be formed from 6 hydrogen atoms is \( 6 \div 2 = 3 \) molecules of water (H2O).
In order to have the balanced chemical equation, we also need to ensure that there are enough oxygen atoms. Since each water molecule requires 1 oxygen atom, producing 3 molecules of water will require 3 oxygen atoms. Thus, to balance it, we would also need 1.5 molecules of O2 (since each O2 molecule has 2 oxygen atoms).
The balanced equation would therefore be:
\[ 3H_2 + 1.5O_2 \rightarrow 3H_2O \]
Now, let's evaluate the provided statements:
-
Each oxygen molecule will combine with 2 hydrogen molecules with no leftover molecules.
- This statement is incorrect because 1.5 O2 molecules are needed to combine with 3 H2 molecules.
-
It is not possible to produce water without leftover molecules.
- This statement would be correct if you consider that you cannot have half molecules in a practical sense, but the equation can be balanced with fractional coefficients.
-
The equation will produce three molecules of water.
- This statement is correct as we have established that 3 H2O will be produced.
-
The result of the equation will be the same.
- This statement is incorrect because changing the number of H2 molecules alters the balancing and the amounts of reactants needed.
The correct statement is:
The equation will produce three molecules of water.