Heat givenoff=masswater*specificheat*deltaTEmp
heat to melt ice= massice*Hf
set the heat to melt ice=heatgiven off
and solve for themass of ice.
watch units.
When ice melts, it absorbs 0.33 kJ per gram.
How much ice is required to cool a 11.0 oz drink from 75 degree Fahrenheit to 37 degree Fahrenheit, if the heat capacity of the drink is 4.18 J/g degree celsius ? (Assume that the heat transfer is 100 % efficient.)
2 answers
84
9 answers