Balance the equation;
2HCl + Mg>>>Mg(Cl)2 + H2
so it takes two moles of HCL per mole of Mg.
how many moles does one have in 2.60gMg
ans: 2.60/atomicmassMg
Now take twice of that for moles of acid.
Molarityacid=molesacid/volume
volume=molesacid/4.8
When hydrochloric acid reacts with magnesium metal, hydrogen gas and aqueous magnesium chloride are produced. What volume of 4.8 M is required to react completely with 2.60 g of magnesium?
1 answer