one gets 1.5 moles O2 for each mole of KCl.
moles KCl=61.7/formulamassKCL
moles O2= 1.5 times that
mass O2=moles O2 * 32
when heated, kclo3 decomposes into kcl ad 02. 2kclo3--> 2kcl+3o2
if this reaction produced 61.7 g of kcl, how much o2 was produced (in grams)?
1 answer