HCLend----|---------NH3end
| on the above diagram shows the meeting point where the NH4Cl forms.
distance = rate x time or
rate = d/time
Let x = distance traveled by HCl
40-x = distance traveled by NH3
rate HCl = x/tHCl
rate NH3 = (40-x)/tNH3
But time traveled by HCl and time traveled by NH3 are the same so
[(x/(40-x)] = √17/36.5
Solve for x and 40-x
Post your work if you get stuck. The meeting point should be closer to the HCl end than to the NH3 end.
When HCl and NH3 are simultaneously placed at the opposite ends of a glass tube 40.0 cm long, a white ring of NH4 Cl forms in the tube. How far is this ring from the end of HCl?
1 answer
1 answer