When comparing the boiling points of two compounds,one is a gas and the other is a liquid,is there anything like the liquid will have a lower boiling point than the solid?
The molecular mass of the liquid is lower than the solid and they have the same type of intermolecular forces.
8 answers
I don't understand the question. At what temperature is one a liquid and the other a gas? Is it the gas going to a solid or the liquid going to the solid.
At the same temperature one is a liquid and other is a liquid.
Being a liquid and having one more step to become vapour,is that a reason for the liquid to have a lower boiling point than the solid?
Being a liquid and having one more step to become vapour,is that a reason for the liquid to have a lower boiling point than the solid?
I think we have to assume that they are under the same pressure to compare their boiling points. I should've mentioned that!
I've made a very bad mistake.It should be corrected as one is a solid and the other is liquid.
I apologize for the inconveniences made!
I apologize for the inconveniences made!
Question: At the same temperature and under same pressure, one is a liquid and the other is a solid.The molecular mass of the liquid is lower than the solid and they have the same kind of intermolecular forces. Can we simply say the liquid has a lower boiling point than the solid,ignoring the given info(mass and intermolecular forces), because it has one more step for becoming vapour(a gas),while the solid have to go from solid to liquid and liquid to gas(two steps)?
I'm still confused, somewhat, but my gut feeling is you can not make any general statements about it. I think you can find some cases in which that is true and some in which it isn't true. At the moment, however, I can't come up with examples of either so I'm not all that comfortable with my answer.
How about I2 and Br2 for an example,at room temperature?
Br2 is a liquid at room temperature and it's molecular mass is lower than I2(s) and they have same kind of intermolecular forces too.
Br2 is a liquid at room temperature and it's molecular mass is lower than I2(s) and they have same kind of intermolecular forces too.
At the same temperature one is a liquid and other is a liquid.
Being a liquid and having one more step to become vapour,is that a reason for the liquid to have a lower boiling point than the solid?
Being a liquid and having one more step to become vapour,is that a reason for the liquid to have a lower boiling point than the solid?
0 answers