To solve this problem, we need to find out how many years it takes for Clark to collect 577 coins.
Let's start by finding out how many coins Clark collects each year.
At 7 years old, Clark has 22 coins.
At 8 years old, he has 22 + 15 = <<22+15=37>>37 coins.
At 9 years old, he has 37 + 15 = <<37+15=52>>52 coins.
And so on.
We can see that Clark adds 15 coins to his collection each year. Therefore, the number of coins he has at a certain age is 22 + 15 * (age - 7). We can write this equation as:
22 + 15 * (age - 7) = 577.
Now, let's solve for age:
15 * (age - 7) = 577 - 22,
15 * (age - 7) = 555,
age - 7 = 37,
age = 37 + 7,
age = 44.
Therefore, Clark will be 44 years old when he has 577 coins.
The correct answer is E. 44.
When Clark was 7 years old he had 22 rare coins. Each year Clark added 15 coins to his collection. Assuming Clark does not sell or lose any coins, how old will Clark be when he has 577 coins?
Responses
A 3030
B 3131
C 3737
D 3838
E 44
1 answer