When chasing a hare along a flat stretch of ground, a greyhound leaps into the air at a speed of 13.3 m/s, at an angle of 34.0° above the horizontal. (a) What is the range of his leap and (b) for how much time is he in the air?

Answer 1

a. Range = Vo^2*sin(2A)/g = 13.3^2*sin(68)/9.8 = 16.7 m.

b. Xo = 13.3*Cos34 = 11.0 m/s. = Hor. component of Vo.
Range = Xo*T = 16.7,
11.0 * T = 16.7,
T = 1.52 s.