When Carbon-14 (^{14}{6}C) undergoes beta decay, it forms Nitrogen-14 (^{14}{7}N) and an electron (e^-) along with an electron antineutrino (ν_e). The electron and the electron antineutrino are the products of one of the neutrons in the carbon-14 atom decaying to a proton1. So, the nuclear equation for this decay process is:

Answer 1

^{14}_{6}C -> ^{14}_{7}N + e^- + \bar{\nu}_e