When calcium iodate is added to water at 25 degrees Celsius, the equilibrium concentration of calcium ion was found to be 0.011M. Calculate the value of Ksp for this salt.

Answer 1

.......Ca(IO3)2 ==> Ca^2+ + 2IO3^-
I......solid.........0.......0
C......solid.........x.......2x
E......solid.........x.......2x

Ksp = (Ca^2+)(IO3^-)^2
Ksp = (x)(2x)^2 = 4x^3 and the problem tells you x is 0.11M. Substitute and solve for Ksp.

Answer 2

Thank you!