I know it's cool to use lower case for everything; however, CO, Co and co mean different things in chemistry. When you type chemistry questions you should find the caps key and use it.
CaCO3 ==> CaO + CO2
mols CaCO3 = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols CaCO3 to mols CO2.
Then convert mols CO2 to L knowing that 1 mol occupies 22.4L at STP.
when calcium carbonate, caco3(s) is heated, it decomposes to form calcium oxide, cao(s) and carbon dioxide gas. how many liters of carbon dioxide will be produced at stp if 2.38 kg of calcium carbonate reacts completely?
1 answer
1 answer