Write the molecular equation and balance it.
CrBr3(aq) + K3PO4(aq) ==> CrPO4(s) + 3KBr(aq)
Separate into the complete ionic equation. It should be obvious that the aq solutions ionize and the solid is shows as the molecule since it doesn't dissolve.
Cr^3+(aq) + 3Br^-(aq) + 3K^+(aq) + PO4^3-(aq) ==> CrPO4(s) + 3K^+(aq) + 3Br^-(aq)
Now look and cancel those ions common to both sides. I see thed 3Br^- on left and right and 3 K^+ left and right. Mark those off. What is left is the net ionic equation.
Cr^3+(aq) + PO4^3-(aq) ==> CrPO4(s)
When aqueous solutions of chromium(III) bromide and potassium phosphate are combined, solid chromium(III) phosphate and a solution of potassium bromide are formed. The net ionic equation for this reaction is:
2 answers
When aqueous solutions of chromium(III) sulfate and sodium phosphate are combined, solid chromium(III) phosphate and a solution of sodium sulfate are formed. The net ionic equation for this reaction is: