The Property of Negative Integer Exponents states that \( a^{-n} = \frac{1}{a^n} \).
Using this property for \( 9^{-2} \), we can write:
\[ 9^{-2} = \frac{1}{9^2} \]
Calculating \( 9^2 \):
\[ 9^2 = 81 \]
Thus,
\[ 9^{-2} = \frac{1}{81} \]
So, the correct answer is:
Start Fraction 1 over 81 End Fraction.