when an object is dropped frome a hight of 20m above the surface of planet Z, it will fall 5m during the 2nd second of fall. What is the acceleration of a falling object near the surface of this planet?

Answer 1

h(2)-h(1)=5 given
1/2 g*2^2 - 1/2 g*1^2=5

g(2-.5)=5 you do the rest.