When an electron moves 2.5 m in the direction of an electric field, the change in electrical potential energy of the electron is 8x10-17J. What is the strength of the electric field that causes the change in potential energy?

Question

320 N/C

200 N/C

20 N/C

3.2 N/C

I'm clueless, but if I had to guess, I would choose 20 N/C

Answer 1

ΔPE=e•Δφ=e•E•d
E= ΔPE/e•d= 8•10⁻¹⁷/1.6•10⁻¹⁹•2.5=200N/C

Answer 2

Thank you! :)