ΔPE=e•Δφ=e•E•d
E= ΔPE/e•d= 8•10⁻¹⁷/1.6•10⁻¹⁹•2.5=200N/C
When an electron moves 2.5 m in the direction of an electric field, the change in electrical potential energy of the electron is 8x10-17J. What is the strength of the electric field that causes the change in potential energy?
320 N/C
200 N/C
20 N/C
3.2 N/C
I'm clueless, but if I had to guess, I would choose 20 N/C
2 answers
Thank you! :)